Tuesday, November 1, 2011

Adopt-a-Physicist open until Nov 22

We have a unique opportunity to talk to 5 different people who have physics backgrounds. They would like to share their knowledge and opinions. Please take advantage of this offer.

To log on: go to www.adoptaphysicist.org
Log in by scrolling down to our Class: NY: Smithtown AP-C Physics
and our Class PIN (supplied in class).

Read about our physicists and write to them. Write thoughtfully. Find out about their careers, their education, and ask for their suggestions for you. They are happy to answer just about any relevant question, often at length. Keep up a conversation.

Our physicists are:

Dr. Bill Freeman. Manager for a $278M particle accelerator project at Fermilab.

Dr. Bryan Gorman. Mathematical modeling (statistical prediction). One example was for the US Coast Guard for improved search and rescue and drug interdiction.

Dr. Michaela Kleinert. Physics professor at Willamette University in OR. Her interests are in atomic/molecular physics and optics.

Mr. Scott Dodd. Medical Physicist, works in radiation oncology at a cancer treatment center.

Dr. von Foerster. Retired; former university professor and publisher.

Sunday, October 23, 2011

HW6 #1

Does anyone know how to solve #1? I have already tried change in energy over time, P=Fv, etc...

HW6 #17

Hey I am having a problem getting #17 to work out on the homework with my numbers. When I tried solving it with other people's numbers the same way, I got the right answer, but mine arent working out. I have an 18 kg child on a playground swing moving with a speed of 4.7 m/s at the lowest point, and the swing is 1 meter long. I need to find the angle the string makes with the vertical. First I tried using conservation of energy with K=U, so .5mv^2=mgh. The m's cancel out and I am trying to solve for h, height above the lowest point. I end up with .5(4.7^2)=9.81h, and when I solve for h, I get 1.12, which doesn't work because it is higher than the length of the string. I also tried solving it by setting cos(theta)=(centripital acceleration)/g, and the acceleration is greater than g so it doesnt work. Please let me know if I am doing something wrong! Thanks!

Sunday, October 16, 2011

HW5 #18

Hey everyone, I just wanted to share a helpful tip for #18. Be careful when converting cubic kilometers to cubic meters. It's not a 1:1,000 ratio because the value is cubed.

Friday, October 14, 2011

HW5 #14

For what length of time should the power be calculated? Is this question asking for the power generated per second/hour/day?

Sunday, October 9, 2011

HW4 #5

Can somebody please help me with this question? I was able to answer the three preceding steps, but I seem to be stuck on this one. I attempted to calculate the horizontal components of T1 and T2 using trigonometry, but this yielded an incorrect solution. I then tried adding these values together, but this was wrong too. Please help!

HW4 #17

Can anyone give me some help on how to do 17? thanks